Question

if Percentage error in side of cub is 3% then maximum Percentage error in volume of cu(d) 12% (c)9% (a)3% (b) 6%​

Answer 1

Answer:

If the percentage error in the side is a cube is 3%, what is the percentage error in its volume?

The volume of a cube is given as

A=s3

where s is the length of one side

Taking the derivative and rearranging

dAds=3s2dA=3s2ds

Since the change in the length of the side is 3% of the side, the change can be written as 0.03s

Substituting this in

dA=3s2(0.03s)dA=0.09s3

Therefore, the “percentage error” of the volume is 9%

Explanation:

please brainliest mark

Answer 2

Answer:

$\huge\red{answer}$

The volume of a cube is given as

A=s3

where s is the length of one side

Taking the derivative and rearranging

dAds=3s2dA=3s2ds

Since the change in the length of the side is 3% of the side, the change can be written as 0.03s

Substituting this in

dA=3s2(0.03s)dA=0.09s3