Question

If percentage error in the measurement of mass is 20% and in velocity is 15%, then
percentage error in the momentum will be​

Answer 1

Answer:

p=m×v

in error we can write in percentage

delta P/P×100 =dealta M/ M ×100+ dealta V/V ×100

delta P/P ×100= 20+15=35%

Answer 2

Percentage error, $\dfrac{\Delta p}{p}=35\%$

Explanation:

The product of mass and velocity is called momentum of an object. Its expression is given by :

$p=mv$

Taking log both sides,

$log\ p=log\ m+log\ v$

Now, Differentiating the both sides of the Equation,

$\dfrac{\Delta p}{p}=\dfrac{\Delta m}{m}+\dfrac{\Delta v}{v}$

$\dfrac{\Delta p}{p}=20+15$

$\dfrac{\Delta p}{p}=35\%$

So, the percentage error in the momentum will be 35%. Hence, this is the required solution.

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Topic : Percentage error

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