Physics, asked by abu007, 10 months ago

If percentage error in the measurement of side of a cube and
its density are each equal to 1%, then the maximum percentage
error in the measurement of its mass is​

Answers

Answered by Anonymous
3

Answer:

The density and mass ranges from the volume of a cube taken with right percent of error in measuring. This is necessary for taking right one and maximum error in the measurement has been placed in the mass and length of a cube is 2% and 3% respectively. Therefore, the final answer is 4% maximum percentage uncertainty.

I hope it will be helpful to you friend

Answered by nirman95
8

Given:

Percentage error in the measurement of side of a cube and its density are each equal to 1%.

To find:

Max error % in calculation of mass

Calculation:

 \therefore \: mass = volume \times density

 =  > m =  {l}^{3}  \times  \rho

So, for small errors (<6%) of length and density , we can say that:

 =  &gt;  \dfrac{\Delta m}{m}  = 3 (\dfrac{\Delta l}{l} ) +  \dfrac{\Delta \rho}{ \rho}

 =  &gt;  \dfrac{\Delta m}{m}  = 3 (1\%) +  1\%

 =  &gt;  \dfrac{\Delta m}{m}  =  3\%+  1\%

 =  &gt;  \dfrac{\Delta m}{m}  = 4\%

So, final answer is:

 \boxed{ \bf{  max \: error \: for \: mass = 4\%}}

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