Question

If percentage error in the measurement of side of a cube and its density are each equal to 1%, then the maximum percentage error in the measurement of its mass is?​

Answer 1

Answer:

I hope it will be helpful to you friend

Answer 2

Answer:  4%

Explanation:

Let side=a, density = D , % error in a = (da/a)x100 = 1% ,                                                            .                                        % error in D = (dD/D)x100=1%.

Mass=m                          % error in m = (dm/m)x100

m=D.a^3

(dm/m)x100= % error in D = (dD/D)x100=1% + 3x[(da/a)x100 = 1%]

                                                                                           {propagation of errors}

                  = 1 + 3 = 4