Question

If percentage error in the measurement of speed of a body is 30% then what will be percentage error in the measurement of its kinetic energy?​

Answer 1

Explanation:

Correct option is

A

60%

Given: speed =v⇒

v

dv

x∣0;%=30%

mass =m−

m

dm

×100%=0

kinetic energ y=k=

2

1

mv

2

Taking log both side and differentiating

k

δk

=

m

δm

+2

v

δv

K

δK

×100

=

m

δm

×100%+2

v

δv

×100%

=2×30%

=60%