Question

If perimeter and area of a circle ⭕ are numerically equal then radius of circle will be​

Answer 1

The radius of the circle is 2 units if the perimeter and the area of a circle are numerically equal.

Hope it helps you!!

Answer 2

Areas related to circles

To solve this type of question always remember the following formulas:

$\boxed{\begin{array}{l} \bullet \: \: \rm{Area_{(circle)} = 2 \pi r^2} \\ \\ \bullet \: \: \rm{Perimeter_{(circle)} = 2 \pi r}\end{array}}$

It is given that, the perimeter and area of of a circle are numerically equal. Therefore,

$\begin{array}{l} \implies \rm{Perimeter_{(circle)} = Area_{(circle)}} \\ \\ \implies 2 \cancel{\pi r} = \cancel{\pi {r}^{2}} \\ \\ \implies \boxed{2 = r}\end{array}$

Hence, the radius of circle is 2 units.

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MORE TO KNOW

$\boxed{\begin{array}{l}\\ \Large\dag\quad\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star \: \: \sf Circle = \pi r^2 \\ \\ \star \: \; \sf Square=(side)^2\\ \\ \star\; \; \sf Rectangle=Length\times Breadth \\\\ \star \: \: \sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \: \: \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \: \: \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star \: \: \sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star \: \: \sf Parallelogram =Breadth\times Height\\\\ \star \: \: \sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star \: \: \sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}$