Question

if perimeter of a rhombus is 100 cm and length of one diagonal is 48 cm what is the area of the quadrilateral?​

Answer 1

Answer:

338square cm

Explanation:

if we divide the rhombus into two parts

sides of the rhombus =25cm

in the first triangle

perimeter =98cm

semi=98÷2

=49

area=

$\sqrt{49(49 - 25)(49 - 25})(49 - 48)$

root of 49×24×24×1

=root of7×7×6×4×6×4

=4×6×7

=168cm square

therefore area of rhombus =

$2 \times 168$

338cm square