Question

If perimeter of a rhombus is 100 cm and length of one diagonal is 48 cm, what is the area of the quadrilateral?

Answer 1

Answer:

The area of quadrilateral is 336 cm².

Step-by-step explanation:

A rhombus has four equal sides. The perimeter of a rhombus is 100 cm.

$4a=100$

$a=25$

The measure of each side is 25.

$4a^2=d_1^2+d_2^2$

Where, a is side length and d₁ and d₂ are diagonals.

$4(25)^2=(48)^2+d_2^2$

$2500=2304+d_2^2$

$d_2=\sqrt{2500-2304}$

$d_2=14$

The area of rhombus is

$A=\frac{1}{2}(d_1d_2)$

$A=\frac{1}{2}\times 48\times 14$

$A=336$

Therefor the area of quadrilateral is 336 cm².

Answer 2

Answer:

336 cm 2

Step-by-step explanation:

pls. see the attached document for detailed information.