if perimeter of a rhombus is 100cm and length of one diagonal is 48cm, what is the area of the quadrilateral?
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The area of quadrilateral is 336 cm square
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(D1)(D2) / 2 = area
Another diagonal = 2[root of(perimeter/4)^2 - (given diagonal/2)^2]
=2[root of (100/4)^2 - (48/2)^2]
=2[root of 25^2 - 24^2]
=2[root of 625-576]
=2[root of 49]
=2(7)=14
Therefore area of rhombus= 14*48/2=336 cm^2
Another diagonal = 2[root of(perimeter/4)^2 - (given diagonal/2)^2]
=2[root of (100/4)^2 - (48/2)^2]
=2[root of 25^2 - 24^2]
=2[root of 625-576]
=2[root of 49]
=2(7)=14
Therefore area of rhombus= 14*48/2=336 cm^2
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