if perimeter of a rhombus is 104 cm and length of 1 diagonal is 20 cm what is the area of Rhombus
Answers
Answer:
Step-by-step explanation:
Step-by-step explanation:
as we know that each sides of a rhombus are equal to each other and it has four sides in all, so here the length of a single side is =(104/4)=26 cm.
And we also know that diagonals of a rhombus intersects each other in half of their length. So half of it will be =(48/2)=24
now applying pythagoras theorem (as two diagonals of a rhombus intersects in 90 degree.),
s=√((26)^2-(24)^2)=10 cm
so the other diagonal will be (10*2)=20 cm (ans)
Answer:
Given:
- Perimeter = 104 cm
- Therefore, each side = 104/4 = 26 cm
- One of the diagonals = 20 cm
- Therefore half of it = 20/2 = 10cm
Solution:
Angle between two diagonals will be 90°
Since each diagonal perpendicularly bisects the other diagonal
Therefore, By Pythagoras Theorem
10² + (D2/2)² = 26²
100 +(D2/2)² = 676
(D2/2)² = 576
(D2/2)² = 24²
D2/2 = 24
D2 = 48 cm
Now we have:
- D1 = 20 cm
- D2 = 48cm
Area of Rhombus = (D1 • D2) / 2
= (20 • 48) / 2
= (960) / 2
= 480 cm²
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