Question

if perimeter of rhombus is 100 cm and length of diagonal is 48 cm what is area of quadrilateral​

Answer 1

Answer:

perimeter =4*side

100=4*side

100/4=side

side =25

ao=1/2*ac-----------digonals of rhombus bisect each other

=1/2*48

=24cm

By Pythagoras therom

25*25=24*24

625-576=bo*bo

49=bo*bo

bo=7

bd=2*bd

bd=14

ac=48

area of rhombus =1/2*productof lengths of digonals

1/2*14*24

336CM sq

Step-by-step explanation:

perimeter =4*side

100=4*side

100/4=side

side =25

ao=1/2*ac-----------digonals of rhombus bisect each other

=1/2*48

=24cm

By Pythagoras therom

25*25=24*24

625-576=bo*bo

49=bo*bo

bo=7

bd=2*bd

bd=14

ac=48

area of rhombus =1/2*productof lengths of digonals

1/2*14*24

336CM sq