Question

if perimeter of rhombus is 100 cm and length of one diagonal is 48 cm what is the area of quadrilateral ?​

Answer 1

rhombus. 4 x. S =. 100

s. =. 100÷4. =. 25cm

area of rhombus. 1÷2 x48x25

600cm2

Answer 2

STEP BY STEP EXPLAINATION
We have given that,
perimeter of rhombus is 100cm
and we know that,
A rhombus has four equal sides.
So,
4a = 100cm
$a \: = \: \frac{100}{4}$
a = 25
The measure of each side is 25cm.
${4a}^{2} = \: {d1}^{2} + \: {d2}^{2}$
Where 'a' is side length and d1 and d2 are diagonals.
$4 ( {25}^{2} ) = \: {48}^{2} + \: {d2}^{2} \\ 2500 \: = \: 2304 + {d2}^{2} \\ d2 \: = \: \sqrt{2500 - 2304 } \\ d2 \: = 14 \\ the \: area \: of \: rhombus \: is \: \: \: \: \\ a \: = \: \frac{1}{2} \times d1 \times d2 \\ a \: = \: \frac{1}{2} \: \times \: 48 \times 14 \\ a \: = {336cm }^{2} \\ therefore \: the \: area \: of \: quadrilateral \: is \: {336cm}^{2}$
i hope it helps you

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