if perimeter of rhombus is 100cm and one of its diagonal is 40cm.find the area of rhombus...
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Perimeter = 100 cm
In Rhombus all sides are equal so for getting lenght of one side we need to divide perimeter by 4 sides.
= 100 / 4
= 25 cm is lenght of each side.
Area of Rhombus = lenght of each diagonal / 2.
Inside the rhombus there forms a triangle with hypotenuse 25cm.
And one of side as 20cm. Which is half lenght of one diagonal.
So by Pythagoras method half lenght of other diagonal is
15cm.
So other diagonal would be 2 × 15 = 30cm.
Area = 30 × 40 / 2 = 600 sq. cm.
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