If perimeter of the triangle is always _______
the sum of median
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If perimeter of the triangle is always greater the sum of median.
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The perimeter of the triangle is "always greater than" the sum of the median.
Step-by-step explanation:
We know that,
The perimeter of Δ We know that,
The perimeter of Δ = ABC = AB + BC + CA
∴ AB + AC > 2AD
Similarly,
BC + A >2CF
Also,
BC + AB>2BE
Adding, we get
(AB + BC) + (BC + AC) + (BC + AB) > 2AD + 2CD + 2BE
2 (AB + BC + AC) >2(AD + BE + CF)
∴ AB + BC + AC >AD + BE + CF
Thus, the perimeter of the triangle is "always greater than" the sum of median.
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