Question

if perpendicular = 15 and Hypotenuse = 17, then find base​

Answer 1

Answer:

$base = \sqrt{ {(hypotenuse)}^{2} - {(perpendicular)}^{2} } \\ base = \sqrt{ {17}^{2} - {15}^{2} } = \sqrt{289 - 225} = \sqrt{64} = 8$

hope this will help you

Answer 2

$base = \sqrt{ {(hypotenuse)}^{2} - {(perpendicular)}^{2} } \\ base = \sqrt{ {17}^{2} - {15}^{2} } = \sqrt{289 - 225} = \sqrt{64} = 8$