Question

if perpendicular is 12 m and hypotenuse is 13 m what would be the base

Answer 1

Answer:

H²=P²+B²

B²=H²-P²

B²=(13)²-(12)²

B=√169-144

B=√25

B=5 m

hope this helps u ....

Answer 2

Answer:

5

Step-by-step explanation:

a^2+b^2=c^2

12^2+x^2=13^2

144+x=169

x^2=169-144=25

x=5