if peter give one marble to david they both will have same no of marbles..and if david gives one marble to peter ,peter will have twice of david..find no of marbles each have??
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Hey friend,
You can see the pic attached for your answer
I have corrected it in the second pic and ur answer is y=5 and x=7
You can see the pic attached for your answer
I have corrected it in the second pic and ur answer is y=5 and x=7
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shreya496:
thnku..
wlcm plz mark it brainliest
no its wrong answer. if david gives one marble to peter then david has 3 marbles and peter has 7 then how is 7 twice of 3
so the answer should be david has 5 marbles and peter has 7 marbles . so that if peter gives one marble to david then both have same marbles that is 6 and if david gives one to peter then david has 4 marbles and pater has 8 which is twice of 4
then plzz show me the process plzz..how it will come 5&7
let peter has x marbles and david has y. now x-1=y+1. again 2(y-1)=x+1. by substracting these two equations you will get y=5 then you have to put the value of y in the 1st equation
thrn you will get the vue of x
the solution of the equation is (x-y-2)- (x-2y-3)=0 now both the x wil be cancelled and remaining will be y-5=0. so that y=5
well, i have corrected in the answer
sry instead of x-2y-3 it will be x-2y+3
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i have solved it see the answer and mark it as beainliest plz
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