If pH=8.19, what is [H3O+]?
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Hi,,
pH = -log [ H3O ]
so,
8.19 = -log [ H3O]
So,,
[ H3O ] = shift + log (-pH)
= shift + log (-8.19)
[ H3O] = 6.45 × 10^-9 mol/l
Hope the answer is helpful
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