Question

if photo electrons are to be emitted from potassium surface with a speed of 6×10^5 m/s what frequency of radiation must be
used
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Answer 1

Answer:2hv0​=hv0​+21​m(4×106)2

5hv0​=hv0​+21​mv2⇒4×21​m(4×106)

=21​mv2⇒v=8×106m/s

Explanation:

Answer 2

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