Question

IF pis pume number and pe
be
divides then bdivides​

Answer 1

Answer:

We suppose the situation that p divides a and a+1 both Thus we get,

a = pr and a+1 = ps

Now you can just subtract both the equations like this:

(a+1)-a = ps - pr

Using that we get,

1 = p(s-r)

This shows that p divides 1 (as (s-r) is an Integer), which is impossible.

This proves that our assumption is wrong and p can only divide a and not a+1.