If PO=PR in the given figure, then find ZOPR
(a) 40°
(b) 30°
(c) 20°
(d)50°
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Answered by
2
if <PRS = 100 deg.
then , <PRQ = 180 - 100 = 80 deg.
as we know that PQ = PR
then triangle PQR IS ISOSCELES
Then , <PQR = <PRQ = 80 deg.
we know that,
sum of angles in a triangle is equal to 180
so , <QPR + <PRQ + <PQR = 180
<QPR + 80 + 80 = 180
<QPR = 20 DEG.
Answered by
0
answer : (c)20
as po=PR
then angle PQR=PRQ
ANGLE PRQ = 180 -100 (EXTERIOR ANGLE OF TRIANGLE)
ANGLE PRQ = 80
PRQ = PQR = 80
THEN
PRQ + PQR + QPR = 180 ( MEASURE OF TRIANGLE)
80+80+X= 180
160 + X = 180
X = 20
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