If point (2 ,0) lies on graph of equation 2x + 3 y = k; find value of k?
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Answered by
3
(x,y) = (2,0)
x=2
y=0
k = 2x + 3y
= 4 + 0
= 4
k=4
Answered by
2
answer k=4
explantation
(x, y) =(2,0)
x=2
y= 0
k=2x+3y
=4+0
=4
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