if point (2k-3,k+2) lies on the graph of the equation 2x+3y+15 =0,find the value of k and represent it graphically
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Answer:
2x+3y+15=0
2(2k-3)+3(k+2)+15=0
4k-6+3k+6+15=0
7k=-15
k=-15/7
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