Question

If point 2k,k-3 lies on graph of equation 2x+3y+15=0, find the value of k

Answer 1

2x+3y+15=0
2k and k-3 lies in this line so
2(2k)+3(k-3)+15=0
4k+3k+6=0
7k=-6
k=-6/7

Answer 2

the question means that
$2 \times 2k + 3 \times (k - 3) + 15 = 0 \\ 4k + 3k - 9 + 15 = 0 \\ 7k + 6 = 0 \\ 7k = - 6 \\ so \: k = \frac{ - 6}{7}$
I HOPE IT WILL HELP YOU.