Question

If point (3,k ) lies on the graph of 2x-3y-12=0 find the value of k

Answer 1

............. it's ur answer....

Answer 2

$2x - 3y = 12 \\ putting \: the \: value \: \\ 2 \times 3 - 3 \times k = 12 \\ 6 - 3k = 12 \\ - 3k = 6 \\ k = \frac{ - 6}{3} \\ k = - 2$

Hope it will help you...