Math, asked by farzeenali356, 10 months ago

If point A(x,y) is equidistant from (a,0) &(2a,a)x+2y-2a=0

Answers

Answered by priyanshu3413

1

Answer:

sorry about this i don't know

Answered by Anonymous

0

Answer:

A(x,y) is equidistant from b(a,0) &c(2a,a)

x-a)^2+y^2=(x-2a)^2+(y-a)^2

x^2+y^2+a^2-2ax=x^2+y^2+a^2-2ay+4a^2-4ax

=-2ax-2ay+4a^2

=-x-y+2a

Step-by-step explanation:

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