Question

 If point P(4,-2)is lies midway the joining A(3,-2) and B(x,-2). Find value of x. 

Answer 1

Answer:

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Answer 2

Answer:-

Given points => A(3 , - 2) ; B(x , - 2).

Mid point of the line segment = P(4 , - 2)

We know that ,

Midpoint of a line segment joining the points $\sf{A(x_1 ; y_1) , B(x_2 ; y_2)}$ is given by $\\\sf{P(a , b) = (\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2})}$

$\implies\sf{P(4 \: , \: - 2) = ( \frac{3 + x}{2} \: \: \frac{ - 2 - 2}{2}) } \\ \\ \implies \sf{P(4 \: ,\: - 2) = ( \frac{3 + x}{2} \: , \: - 2) }\\ \\\implies \sf{ 4 = \frac{3 + x}{2}} \\ \\ \implies\sf{3 + x = 8} \\ \\ \implies\sf{x = 8 - 3} \\ \\ \implies\sf{x = 5}$

Hence, the value of x is 5.