If point P(4,-2)is one end of focal chord PQ of parabola y²=x , then slope of tangent at Q is
Answers
Given : point P(4,-2)is one end of focal chord PQ of parabola y²=x
To find : Slope of Tangent Q
Solution:
Let say point Q = ( x, y )
y²=x
Comparing with
y² = 4ax
=> 4a = 1
=> a = 1 /4
Hence Focal chord passes through S ( 1/4 , 0)
Slope of PS = (0-(- 2)) /(1/4 - 4) ) = - 8/15
Slope of PQ = Slope of PS
=> ( y + 2)/(x - 4) = -8/15
=> 15y + 30 = -8x + 32
=> 15y = -8x + 2
=> 15y = -8y² + 2
=> 8y² + 15y - 2 = 0
=> 8y² + 16y - y - 2 = 0
=> 8y (y + 2) - 1 (y + 2) = 0
=> (8y - 1)( y + 2) = 0
y = - 2 is P
y = 1/8
=> y = 1/8 => x = 1/64
Q = (1/64 , 1/8)
y²=x
=> 2y dy/dx = 1
=> dy/dx = 1/2y
at Q y = 1/8
=> dy/dx = 1/2(1/8)
=> dy/dx = 4
slope of tangent at Q is 4
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