Question

if point p(x,y)is equidistant from the points a(a+b,b-a)and(a-b,a+b),prove that bx=ay

Answer 1

HELLO MATE..

REFER TO THE ATTACHMENT...

# GUDIYA...

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Answer 2

☺️☺️hey mate,

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➡️PA = PB

take square both side

➡️PA² = PB²

now use distance formula ,

➡️[ x - ( a + b ) ]² + [ y - ( b - a ) ]² = [ x- ( a - b ) ]² + [ y - ( a + b ) ]²

➡️x² + ( a + b )² - 2x ( a + b ) + y² + ( b -a)² - 2y ( b- a ) y = x² + ( a - b )² - 2x ( a - b ) + y² + ( a + b )² -2y ( a + b )

➡️2x (a-b)-2x ( a + b ) = 2y ( b - a ) - 2y ( a + b )

➡️2x [ a - b - a - b ] = 2y [ b - a - a - b ]

➡️2x ( -2b ) = 2y ( -2a )

➡️bx = ay

hence proved!!!

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thanks!!!

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