Question

IF points (1,4) (r, -2) and (-3, 16) are collinear, find the value of "r"

Answer 1

For 3 points to be collinear the area of triangle made by the vertices must be 0.

So 1(-2-16)+r(16-4)+(-3)(4-(-2))= 0

>>1(-18)+r(12)-3(6)=0

>>-18+12r-18=0

>>12r= 36

:. r= 3.

Answer 2

Answer:

It is given that , a= {1,5}, b={3,7} : r=(a,b) and a-b is multiple of 4.

We have to find relation r.

Solution : Consider the following pairs

(1,3)=1 -3= -2,

(1,7) = 1- 7 = -6

(5,3) = 5 -3 =2

(5,7) = 5 - 7 = -2

As , none of the pair (1,3),(1,7), (5,3),)(5,7) satisfies the condition that a-b is multiple of 4, where a= first element of ordered pair and b= Second element of ordered pair.

So→ [r(a, b) such that a-b is multiple of 4], does not form any kind of relation from a to b.

Step-by-step explanation: