Question

if points ( 7,-2) , (5,1) and (3,k ) are collinear , find the value of k

Answer 1

If 3 points are collinear,the area enclosed between them is 0.

Answer 2

Answer:

Step-by-step explanation:

1/2 |x1(y2-y3)+x2(y3-y1)+x3(y1-y2)| = 0

1/2|7(1-k)+5(k+2)+3(-2-1)| = 0

7-7k+5k+10-9=0

8-2k=0

K= -8/-2

K=4