If points A(-2,1), B(a,0), C(4,b) and D(1,2) are the vertices of a parallelogram ABCD,
find the values of a and b.
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Answer:
(4-2)/2 =(a+1)/2
2=a+1
a =1
(1+b)/2=(0+2)/2
1+b=2
b=1
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