Question

- If points ( x, y) is equidistant from points ( 7, 1) and (3,5), show that y = x - 2). ​

Answer 1

$\huge \underline \mathfrak \pink{♡AnSwer♡}$

⇒Let point P ( x, y) be equidistant from points A = ( 7, 1 ) and B ( 3, 5)

→ ∴ AP = BP

→ ∴ AP ^ 2 = BP ^ 2

∴ ( x - 7 ) ^2 + ( y - 1 ) ^2 = ( x - 3) ^2 + ( y - 5) ^2

∴ x ^2 - 14x + 49 + y^2 - 2y +1 = x^2 - 6x + 9 + y^2 - 10 y + 25

∴ - 8x + 8y = - 16

∴ x - y = 2

Answer 2

Answer:

I hope it will helps you