If polynomial 3xsquare+2x_6 then find the value of asquare÷square + b square÷asquare
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Answer:
Given
polynomial = 3x^2 + 2x -6
a^2 /b^2 + b^2/a^2 = ?
From the given polynomial,
a = 3
b = 2
c =-6
Therefore,
a^2 /b^2 + b^2/a^2 = (a^4 + b^4)/a^2b^2
or , (a^4+b^4)/(ab)^2
substituting values ,
= (3^4 + 2^4)/(3x2)^2
or, (81+16)/36
or, 97/36
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