if polynomial ax^3+3x^2-13 and 2x^3-5x+a when divided by (X+2) leaves the same remainder find value of a
Answers
Answered by
2
Answer:
5/9
Step-by-step explanation:
Since x+2 gives same remainder in both the polynomials
We put x=-2 and equate the remainders
Remainder-polynomial 1: -8a+12-13 = -8a-1
Remainder-polynomial 2: -16+10+a= a-6
a-6=-8a-1
9a= 5, a=5/9
Answered by
2
First , let , g(x) = x + 2 = 0
=> x = -2
Now ,
let P1 (x) = ax³ + 3x² - 13
and P2 (x) = 2x³ - 5x + a
According to the question,
P1 (-2) = P2 (-2)
=> a(-2)³ + 3(-2)² - 13 = 2(-2)³ - 5(-2) + a
=> -8a + 12 - 13 = 16 + 10 + a
=> -9a - 1 = -6
=> a = 5/9
So,the value of a is 5/9.
hope it helps dear... ✌☺️
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