English, asked by hardesuwa805, 11 months ago

If polynomial ax3+3x2-13 and 2x3-5x+a leave same when divided by x-2 find a

Answers

Answered by Anonymous
10

value of x = 2 ( simplifing x - 2 )

so ,

8a + 12 - 13 = 16 - 10 + a ( after putting x= 2 )  

8a - a = 16 -10 -12 + 13  

7a = 6 + 1  

7a = 7  

a = 1  

THANKS ............


harsh7483: it is wrong
Answered by Abhi9022
1

Answer:

1

Explanation:

value of x = 2 ( simplifing x - 2 )

so ,

8a + 12 - 13 = 16 - 10 + a ( after putting x= 2 )  

8a - a = 16 -10 -12 + 13  

7a = 6 + 1  

7a = 7  

a = 1  

Similar questions