If polynomial ax3+3x2-13 and 2x3-5x+a leave same when divided by x-2 find a
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value of x = 2 ( simplifing x - 2 )
so ,
8a + 12 - 13 = 16 - 10 + a ( after putting x= 2 )
8a - a = 16 -10 -12 + 13
7a = 6 + 1
7a = 7
a = 1
THANKS ............
harsh7483:
it is wrong
Answered by
1
Answer:
1
Explanation:
value of x = 2 ( simplifing x - 2 )
so ,
8a + 12 - 13 = 16 - 10 + a ( after putting x= 2 )
8a - a = 16 -10 -12 + 13
7a = 6 + 1
7a = 7
a = 1
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