Question

if polynomial ax3+4x2+kx+5 leaves same remainder when each is divided by x - 4 . find the value of a.​

Answer 1

Answer:

please write the questions full

Answer 2

Answer:

] given ax3+4x2+3x−4=0 &

x3−4x+a=0 leave same 

remainder when divided by x-3

P(x) = ax3+4x2+3x−4

q(x)= x3−4x+a

Remainder theorem,

P(3)=q(3)

a(3)3+4(3)2+3(3)−4=33−4(3)+a

27a+36+9−4=27−12+a

26a=15−41

26a=−26

∴a=−1

P(x)=−x3+4x2+3x−4

when divide by (x-2)

P(2)=−(2)3+4(2)2+3(2)−4

=−8+16+6−4

=8+2

=10