Question

if polynomial p(t)=t⁴-t³+t²+6,then find p(-1)

Answer 1

hope my answer helps

Answer 2

If p(t) = t⁴ - t³ + t² + 6 then p(-1) = 9

Given :

The polynomial p(t) = t⁴ - t³ + t² + 6

To find :

The value of p(-1)

Solution :

Step 1 of 2 :

Write down the given polynomial

The given polynomial is p(t) = t⁴ - t³ + t² + 6

Step 2 of 2 :

Find the value of p(-1)

p(t) = t⁴ - t³ + t² + 6

Putting t = - 1 we get

$\displaystyle \sf{p( - 1) = {( - 1)}^{4} - {( - 1)}^{3} + {( - 1)}^{2} + 6 }$

$\displaystyle \sf{ \implies p( - 1) = 1 - ( - 1) + 1 + 6 }$

$\displaystyle \sf{ \implies p( - 1) = 1 + 1+ 1 + 6 }$

$\displaystyle \sf{ \implies p( - 1) = 9 }$

The value of p(-1) is 9