Question

if polynomial p[x] = 3x3 - x2 - ax -45 has one zero of 3 then a=

Answer 1

Step-by-step explanation:

p[x] = 3x³-x²-ax-45

put x=3

p[3] = 3(3)³-(3)²-a(3)-45=0

=3×27-9-3a-45=0

=81-9-45-3a=0

=81-54-3a=0

=27-3a=0

=27=3a

=a=27/3

=a=9

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