Question

if polynomial p(x) =x^ 3 - 4x^2 + x+6, then the value of
p(0)
is​

Answer 1

$\large\sf\underline{Given:-}$

• $\sf\:p(x)=x^{3}-4x^{2}+x+6$

$\large\sf\underline{To\:find:-}$

• $\sf\:p(0)$

$\large\sf\underline{Solution:-}$

$\sf⟹\:p(0)=0^{3}-4 \times 0^{2}+0+6$

$\sf⟹\:p(0)=0-4 \times 0 + 0+6$

$\sf⟹\:p(0)=0- 0 + 0+6$

$\sf⟹\:p(0)=0+6$

$\tt\pink{⟹\:p(0)=6}$

• Thnku ❣

Answer 2

$\Huge\mathfrak\green{answεr:}$

${}$

$\bf{{\underline{To~solve}}:}$

• $\sf{p(x) =x^ 3 - 4x^2 + x+6}$ when $\sf\green{p(0)}$

$\bf{{\underline{Solution}}:}$

$\rm{~~~~~~~~~~ p(x)=x^{3}-4x^{2}+x+6}$

$\rm\implies{p(0)=(0)^{3}-4(0)^{2}+(0)+6}$

$\rm\implies{p(0)=0-0+0+6}$

$\rm\implies{p(0)=\green{\underline{\boxed{\bf 6}}}}$

$\bf\therefore{{\underline{Required~answer}}:}$

• $\rm{p(0)=\green{\underline{\boxed{\bf 6}}}}$