if polynomialax^2+3x^2-3 and2x^3-5x+a leaves the same remainder when each is divided by x-4,find the value of "a"
victory1venkatesh:
Is it ax^2
Please say
yes
it is ax^2
a=15/4 and -3 ???
sure
Then check out the answer
ok
Answers
Answered by
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Divide to get the remainders as 27x+a and 4(a+3)x-a
Equate them to get the values of a as 15/4 and -3
Equate them to get the values of a as 15/4 and -3
Thank you
ur wlcm
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