if polynomials ax^3+3x^2-3 and 2x^3-5x+a a leaves the same remainder when each is divided by x-4 find the value of a
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p(x)=ax^3+3x^2-3
x-4=0
x=4
p(4)=a(4)^3+3(4)^2-3
R=64a+45........(1)
g(x)=2x^3-5x+a
g(4)=2(4)^3+5(4)+a
R=148+a........(2)
R=R
64a+45=148+a
63a=103
a=103/63
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