Question

If polynomials ax^3+3x^2-3and2x^2-5x+a leaves the same remainder when each is divided by (x-4) find the value of a

Answer 1

x-4= 0

x= 4

P(x) = ax^3+3x^2-3

P(4) = a*64 + 48 - 3

= 64a + 45

again,

P(x) = 2x^2-5x+a

P(4) = 32-20+a

= 12+a

ATP,

64a+45=12+a

64a-a=12-45

63a=33

a=33/64