Question

if POQ is a diameter of the circle and R is a point on the circle, then prove that PR²+QR²=PQ²​

Answer 1

Answer:

45°

Step-by-step explanation:

⇒  In △PQR,

⇒  PR=QR                             [ Given ]

∴     ∠RPQ=∠PQR              [ Opp angles of equal sides are equal ]

⇒   ∠QRP=90o                     [ Angle inscribed in semi-circle ]

⇒  ∠PQR+∠QRP+∠RPQ=180o

⇒  ∠RPQ+90o+∠RPQ=180o

∴    2∠RPQ=180o−90o

∴    2∠RPQ=90o

∴    ∠RPQ=45o

HOPE THIS HELPS