Question

if position of a particle is given by x=t^2+5t+3 where x is in metre and t is in seconds. Calculate 1) velocity of the particle at t=3 seconds 2) average velocity of the particle between t=1second to 3seconds

Answer 1

Answer:

The answer of the given questions is 1. 11

2. 9

Answer 2

Explanation:

1.

x= t^2+5t+3

dx/dt= 2t+5(velocity)

t=3

2*3+5

6+5=11

2.

x=2t+5( v1)

t=1

x=2*1+5=7

x=2t+5(v2)

t=3

2*3+5=11

avg=v1+v2/2

avg=7+11=18/2=9

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