Question

if position of a particle is x = ( t³-2t+1 ) m . Find :- 1) velocity at t = 2 sec and 2) acceleration st t = 2sec. ??​

Answer 1

Position at O sec = 1 m

at 2 sec = 2³-2×2+1 = 5 m

initial vel = 1/1 = 1 m/s

then velocity = 5-1/2 = 4/2 = 2 m/s

and acceleration = v-u/t = 2-1/2 = 0.5 m/s

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Answer 2

Answer:

Hey mate ✌✌

1) v = dx/dt = d/dt ( t³ - 2t + 1 )

V = 3t² - 2 .

At t = 2sec,

V = 3(2)² - 2

V = 10m/s .

2) a = dv/dt = d/dt ( 3t²-2 )

a = 6t

At t = 2 sec,

a = 6(2)

a = 12 m/s² .

Therefore, v = 10m/s and a = 12 m/s²

Explanation: