If position of particle is given by x=3t^2, find acceleration
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x = 3t^2
v = dx/dt = d(3t^2)/dt = 6t
a = dv/dt = d(6t)/dt = 6 m/s^2
So, this means that the acceleration of the body is constant with time.
Hope this helps you !
v = dx/dt = d(3t^2)/dt = 6t
a = dv/dt = d(6t)/dt = 6 m/s^2
So, this means that the acceleration of the body is constant with time.
Hope this helps you !
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