If
Position of particle is given by
x= t² +st+ 3
find Average velocity between
t=1sec to t= 3 second
Answers
Answered by
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u=
dt
dx
=10t+2
avg. velocity=
∫
0
t
dt
∫
0
t
u(t)dt
=
3
∫
0
3
(10t+2)dt
=
3
2
(10t
2
+2t)∣
0
3
=
3
5×9+6
=
dt
dx
=10t+2
avg. velocity=
∫
0
t
dt
∫
0
t
u(t)dt
=
3
∫
0
3
(10t+2)dt
=
3
2
(10t
2
+2t)∣
0
3
=
3
5×9+6
=
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