Question

if position vector of a particle is (3t) 1^ (4t) j^ then obtain its velocity vector of 2s​

Answer 1

Answer:

pls mark as brainliest and follow me .......the velocity is uniform

Answer 2

Answer:

velocity will be constant and it is (3i + 4j)m/s    OR     resultant velocity = 5 m/s

Explanation:

we know, v= dx/dt

v = d (3i + 4j)/dt

  => d (3t i)/dt  +  d(4t j)/dt              (differentiation)

v =>  3i + 4j  m/s

Resultant => v = $\sqrt{3^{2}+4^{2} }$ => 5 m/s

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