Question

if position x of an object changes with time T as X equal to T square + 4T + 5 then the displacement of the particle in the time interval t equal to 1 second to t equal to 4 second is

Answer 1

Explanation:

X(t)=t^2+4t+5

Now.

x(1)=1^2+4(1)+5

=10

x(4)=2^2+4(2)+5=17

Therefore displacement in the interval of t=1 to t=4 is= (17-5)=12

Answer 2

Answer:

Therefore, the required displacement is = 27 units.

Explanation:

Given :

 position of an object:  $x=T^2+4T+5$

where, $T$ is the time interval.

Position of particle at (t = 1 second):

$x_i=(1)^2+4(1)+5=10$

Position of particle at (t = 4second):

$x_f=(4)^2+4(4)+5=37$

The displacement of the particle in the time interval t equal to 1 second to t equal to 4 seconds is = $x_f-x_i$

$\implies x_f-x_i=37-10=27$

Therefore, the required displacement is = 27 units.

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